How to Solve the Two Sum Problem?
The Two Sum problem is a common question asked in technical interviews, particularly for software engineering positions. It challenges candidates to utilize their problem-solving skills and coding knowledge efficiently. In this article, we will explore the problem, present a solution, and provide clear code examples.
The problem can be stated as follows: given an array of integers, nums
, and an integer target
, you need to find two distinct numbers in nums
that sum up to target
. If such a pair exists, you should return their indices in the format of an array. If no such pair exists, typically you would return an empty array.
For example, consider the array nums = [2, 7, 11, 15]
and the target = 9
. The numbers 2
and 7
from the array sum up to 9
, and their indices are 0
and 1
. Hence, the output would be [0, 1]
.
Brute Force Approach
The simplest approach is to use a nested loop to check all possible pairs of numbers in the array to see if their sum equals the target. The time complexity of this solution is O(n^2), which can be inefficient for larger arrays.
Here’s what the implementation looks like:
Python
Optimized Approach Using a Hash Map
While the brute-force method works, there is a more efficient way. By using a hash map (dictionary in Python), we can achieve a time complexity of O(n). The idea is to traverse the array and for each element, check if the complement (i.e., target - current_element
) exists in the hash map. If it does, we return the indices.
Here’s how this can be implemented:
Python
Explanation of the Optimized Approach
-
Initialization: A hash map (
num_map
) is created to store the elements of the array as keys and their respective indices as values. -
Iteration: As the loop iterates through
nums
, for each numbernum
, the complement needed to reach the target is calculated. -
Check for Complement: If the complement exists in
num_map
, it means a previous number can pair with the current number to form the target sum, and we return their indices. -
Store Current Number: If the complement doesn’t exist in
num_map
, the current number is added with its corresponding index.
Edge Cases
When solving the Two Sum problem, it's wise to consider edge cases such as:
- The array contains fewer than two elements.
- There are numbers that can form the sum but do not meet the uniqueness requirement.